# Find each dict based on 'spam' and 'shrubbery' keys. # Find each dict based on 'spam' key only.Īssert find_dict_in_list(dicts, spam=spam) = dicts I've added a little bit of benchmarking below to illustrate pandas' faster runtimes on a larger scale i.e. # The pandas dataframe allows you to pick out specific values like so:ĭf2 = df = 'Pam') & (df = 7) ]ĭf2 = df # Dict items with the same key are entered into the same respective column. To get the list of dictionary values from the list of keys, use the list comprehension statement dkey for key in keys that iterates over each key in the. # Create a data frame, keys are used as column headers. Have you ever tried out the pandas package? It's perfect for this kind of search task and optimized too. from random import randintįor _ in range(1000): # number of dicts in the listįor i in range(10): # number of keys for each dictįor dict_ in (x for x in list_dicts if x = 20):įor dict_ in = 20]:įor dict_ in filter(lambda x: x = 20, list_dicts): A simple solution is to use a generator expression. Please see this graph I calculated: (method names see below).Īll tests done with Python 3.6.4, W7圆4. This post will discuss how to search a value for a given key in a list of dictionaries in Python. The keys per dictionary does not affect speed significantly for large amounts (thousands) of keys.All scale linear with the number of dicts in the list (10x list size -> 10x time).Speed: list comprehension > generator expression > normal list iteration > filter. In the list of dictionaries, we refer first to the index number of the dictionary in square brackets, then the key of the dictionary item (the list is the outer.I tested various methods to go through a list of dictionaries and return the dictionaries where key x has a certain value.
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